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0.25x^2=9
We move all terms to the left:
0.25x^2-(9)=0
a = 0.25; b = 0; c = -9;
Δ = b2-4ac
Δ = 02-4·0.25·(-9)
Δ = 9
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{9}=3$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-3}{2*0.25}=\frac{-3}{0.5} =-6 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+3}{2*0.25}=\frac{3}{0.5} =6 $
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